若x1满足2x+2的x次方=5,x2满足2x+2log2为底(x+1)=5,则x1+x2=?

题目：若X1满足2X+2^X=5,X2满足2x+2log2(x-1)=5,X1+X2=( ) (A)5/2 (B)3 (C)7/2 (D)4令log2(x2-1)=t ∴x2=2^t+1 ∴2(2^t+1)+2t=5 ∴2^(t+1)+2(t+1)=5 ∴t+1=x1 ∴x1+x2 =t+1+2...